![]() |
Home My Faqts Contributors About Help |
| Entry | Add Entry Alert - Edit this Entry |
Feb 25th, 2000 06:59
Andrew Sheh
Tim Fountain
>I tried using this code but it didn't work:
>require("list.php3?cat=adco&area=all");
>It seems this function will only take an actual file name. Is there a
>way around this?
ANSWER
As 'require' simply puts the file in the page you're calling it from,
you can set the variables there. Eg.:
$cat = "adco";
$area = "all";
require("list.php3");
© 1999-2004 Synop Pty Ltd