Entry

How can i declare a 2D dynamic array in C++, like a 1D int *x = new int[10];, but 2D. syntax?

Aug 27th, 2007 14:54
John Doe, dick weed, Jean-Michel Carriere,

int ** array = new int*[rows];
for(int i = 0; i < rows; i++)
   array[i] = new int[cols];
this code creates a dynamically allocated matrix of size rowsXcols.  
Analogous to the non-dynamically allocated array:
int array[rows][cols];
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Or you could just write the following code:
int **array = reinterpret_cast<int**>( new int[rows*cols] );
for( int k = 0; k < rows; k++ )
  array[k] = reinterpret_cast<int*>( array ) + k * cols;
... /* some code */
delete[] reinterpret_cast<int*>( array );