Entry

Directory of current file

Jul 5th, 2000 10:00
Nathan Wallace, unknown unknown, Hans Nowak, Snippet 107, Guido van Rossum

"""
Packages: files;operating_systems.generic
"""
"""
> how about a combination?
> 
> import sys, os
> if __name__ == '__main__':
>     _thisDir = sys.argv[0]
> else:
>     _thisDir = sys.modules[__name__].__file__
Eh, what's wrong with simply using __file__?  It's a global in your
own module, remember!
> _thisDir = os.path.split(_thisDir)[0]
One more refinement: instead of os.path.split(x)[0], use
os.path.dirname(x).
The whole thing could become a one-liner:
"""
import os, sys  # added by PSST
_thisDir = os.path.dirname(__name__ == '__main__' and sys.argv[0] or __file__)
print _thisDir
# empty? -- PSST
"""
You could also use the little-known fact that sys.path[0] is the
script's directory; or the empty string if it's the current directory:
"""
if __name__ == '__main__':
    _thisDir = sys.path[0] or os.curdir
else:
    _thisDir = os.path.dirname(__file__)
print _thisDir