Entry

How can I get rid of "Warning: undefined variable" after receiving data from a form that doesn't contain data?

Apr 2nd, 2001 22:47
Philip Olson, Paul van Oss,

Either define the variables or do what most people do and turn down 
error reporting.  See :
  Reporting Errors                                            :
  -------------------------------------------------------------
  http://www.php.net/manual/en/phpdevel-errors.php
Pay special attention to E_NOTICE.  For example, the following should 
give a similar errors with E_NOTICE on :
  print $array[index]  // Always use quotes, looks for static variable
                       // named 'index' first.  'make' in your case.
                       // sidenote: something like $array[4] is good.
  if ($user == '')     // Use isset or empty or something similar.
  print $notset;       // ""
  if ($submit)         // "" or don't depend on submit buttons.
Messing with empty variables is okay but use quotes around array 
index.  Always.  Except when index is a number (not associative) like 
$array[3].  It works without but having php look for static variables 
first wastes energy and will cause unexpected results if it happens to 
exist.  In otherwords, when calling $info[email] PHP will first look 
for the static variable named email and then use the index email as 
indended.
This setting exists within php.ini, it's the error_reporting setting 
and the following function has useful information within it too :
  error_reporting -- set which PHP errors are reported        :
  -------------------------------------------------------------  
  http://www.php.net/manual/en/function.error-reporting.php